Hi Team,
how can i do a randbetween of a list? its possible?
and then eliminate this number of the list.
br
You can use the function like this:
RANDBETWEEN(1, COUNT([List]))
Then use the INDEX function to get that item in the list:
INDEX([List], RANDBETWEEN(1, COUNT([List])))
Then you can subtract it from the original list but the item has to be in LIST form
[List] - LIST(INDEX([List], RANDBETWEEN(1, COUNT([List]))))
NOTE: I have not tested this
4 Likes
@WillowMobileSystems,
Good one. Nice practical solution.
[List] was my generic reference to some list variable. You need to replace it with whatever your list is. It could be a SELECT() function or a column of some LIST type like EnumList.
1 Like
Hi John,
I don’t know where I’m wrong
i’m attaching you 4 results.
and I dont know how to use index option?
br
In your examples, for each of the columns A, B, C and D, it seems you are reusing the RANDBETWEEN function each time which means it re-generating a new random number in each column.
You need to use the saved [randomNumber] value in columns C and D. For example in Column C the expression should be
INDEX([initialList], [randomNumber])
The expression in Column D should be:
[initialList] - LIST(INDEX([initialList], [randomNumber]))
1 Like
I quickly implemented this in a tester app. It appears to be working well. Note how it works when the list is not in sorted order.
4 Likes
thks a lot John for your help,
its running.
Hi John,
and now, how I can not repeat randomNumber? its possible?
My initial idea was to use [newList] as [initialList] but its impossible, its a circular definition and not works.
br
What are you trying to accomplish here? Something like shuffle play a playlist?
smart solution
Hi Steve,
I have 10 differents cards and 2 players, and i want to deal the cards.
Suppose a Cards table has the columns: Suit, Value, and ID (the combination of the suit and value); and 52 rows for a common deck of cards. To deal player 1, set Player 1 Hand to the output of:
TOP(ORDERBY(Cards[ID], RANDBETWEEN(1, 999999)), 5)
and to deal player 2, set Player 2 Hand to the output of:
TOP(ORDERBY((Cards[ID] - [Player 1 Hand]), RANDBETWEEN(1, 999999)), 5)
See also:
2 Likes
Hi Steave,
why using “TOP(ORDERBY(Cards[ID], RANDBETWEEN(1, 999999)), 5)”,
appears this message “ORDERBY has invalid inputs”?
br
Did you replace Cards[ID] with the appropriate column specification for your app?
Yes I did.
top(orderby(game[card],RANDBETWEEN(1, 999999)), 5)
The the Card column the key column of the Game table?
No Steve, key column is “row_number”.
To check it quickly i simplified situation using only one player.
Try:
top(orderby(game[_rownumber],RANDBETWEEN(1, 999999)), 5)